1) I have 20 rupees. I bought 1, 2, 5 rupee stamps. They are different
in numbers by the reason of no change, the shop keeper gives 3 one rupee
stamps. So how many stamp(s) I have.
Ans: 10
Ans: 10
Explanation:
(a) 3 x 1 rupee, 1 x 2 rupee, 3 x 5 rupee
(b) 3 x 1 rupee, 6 x 2 rupee, 1 x 5 rupee
(c) 4 x 1 rupee, 3 x 2 rupee, 2 x 5 rupee
and one can think of others e.g.
(d) 11 x 1 rupee, 2 x 2 rupee, 1 x 5 rupee
(e) 9 x 1 rupee, 3 x 2 rupee, 1 x 5 rupee
(b) 3 x 1 rupee, 6 x 2 rupee, 1 x 5 rupee
(c) 4 x 1 rupee, 3 x 2 rupee, 2 x 5 rupee
and one can think of others e.g.
(d) 11 x 1 rupee, 2 x 2 rupee, 1 x 5 rupee
(e) 9 x 1 rupee, 3 x 2 rupee, 1 x 5 rupee
the point is that the requirement that the shopkeeper gives 3 one-rupee
stamps eliminates all solutions other than the first two.that in turn forces the solution to contain an odd number of 5 rupee stamps, as no amount of 2-rupee stamps can add up to an odd number of rupees.There is a solution with one 5-rupee stamp (b) and a solution with three 5-rupee stamps (a).
2) An Engine length 1000 m moving at 10 m/s. A bird is flying from
engine to end with x kmph and coming back at 2x. Take total time of bird
traveling as 187.5 s. Find x and 2x.
Ans:8,16.
Explanation:
distance travelled by the bird=2000m
time taken=187 1/2 sec
=375/2 sec
speed is in the ratio of 1:2
dividing the time in the ratio of 1:2
time while moving to end=375/2(2/3)=125 sec
speed=distance/time=1000/125=8 m/sec
speed in the fro direction=16m/sec
time taken=187 1/2 sec
=375/2 sec
speed is in the ratio of 1:2
dividing the time in the ratio of 1:2
time while moving to end=375/2(2/3)=125 sec
speed=distance/time=1000/125=8 m/sec
speed in the fro direction=16m/sec
3) All persons know either swimming or rowing.
There are 14 persons who know only swimming and 14 persons who know only rowing. 8 tickets sold for rowing. How many people are there for swimming?
There are 14 persons who know only swimming and 14 persons who know only rowing. 8 tickets sold for rowing. How many people are there for swimming?
Explanation:
we need atleast one of the values i.e either total no. pf membrs or no.of mem who know both to find the otherwhere n(a U b) = n(a - b) + n(b-a)+n(a intersection b)
Given,8 tickets sold for rowing..from this we can deduce that 6 people who know only rowing did not buy tickets.but we have no idea how many people know both..Even if we knew this, not everyone needs to buy a ticketSo, question is totally incomplete
Given,8 tickets sold for rowing..from this we can deduce that 6 people who know only rowing did not buy tickets.but we have no idea how many people know both..Even if we knew this, not everyone needs to buy a ticketSo, question is totally incomplete
4) Which polygon has no. of sides = diagonal
Ans:Pentagon
Exp:
the number of diagonals from a single vertex is three less than the the number of vertices or sides, or (n-3).
There are N vertices, which gives us n(n-3) diagonals
But each diagonal has two ends, so this would count each one twice. So as a final step we divide by 2, for the final formula:
|
|
where N is the number of sides (or vertices)
5) One Cigar can be made from 7 bits. If there are 16 Cigars then how many bits collected?
Ans: 4
Ans: 4
Exp:
The question is assuming that the bit is what is left after smoking..........
So 16 cigars
are smoked so you have 16 bits left. You take 14 bits to make 2 cigars
and have 2 bits left over.
you smoke the final 2 cigars and now you have
the two bits from them plus the other two left over bits for a total of
4......:)
6) A, B, C, D went to a hotel and planned to share the bill equally. But
afterwards they changed their plan and to pay proportional to
consumption A paid 240, B & C paid equally, D paid only half the
amount that he should have paid based on the first plan. What is the
amount paid by B?
Ans:Rs.160
Exp:
B = C
A = 240
D = 25%/2
It should have been 25% for each, but they paid proportionally.
So if D paid 12.5% of the bill, then that leaves 87.5% of the bill for the other 3.
If B and C paid the same, then A had to take over the other 12.5% of D's bill based on consumption.
25% + 12.5% = 37.5% = % paid by A
37.5% + 12.5% = 50%
100-50 = 50%
Since B and C paid the same, B paid 25% of the bill.
Since we know that 240 rupees is 37.5% of the bill, use a proportion to find the amount of the whole bill.
240/.375 = x/1
x = Rs.640
Do the percentages based on what we know:
A = Rs.240
B = Rs.160
C = Rs.160
D = Rs.80
B paid Rs.160
Lone rider, you don't need the final bill amount to figure out how much B paid.
You only need to know that there are 4 of them. They originally agreed to pay 25% of the bill each.
If D only paid half of the original 25%, then he only paid 12.5%.
If B and C paid the same, either they split the 12.5% in 6.75% each, or A took the 12.5% and tacked it onto his bill, which seems more likely.
A = 240
D = 25%/2
It should have been 25% for each, but they paid proportionally.
So if D paid 12.5% of the bill, then that leaves 87.5% of the bill for the other 3.
If B and C paid the same, then A had to take over the other 12.5% of D's bill based on consumption.
25% + 12.5% = 37.5% = % paid by A
37.5% + 12.5% = 50%
100-50 = 50%
Since B and C paid the same, B paid 25% of the bill.
Since we know that 240 rupees is 37.5% of the bill, use a proportion to find the amount of the whole bill.
240/.375 = x/1
x = Rs.640
Do the percentages based on what we know:
A = Rs.240
B = Rs.160
C = Rs.160
D = Rs.80
B paid Rs.160
Lone rider, you don't need the final bill amount to figure out how much B paid.
You only need to know that there are 4 of them. They originally agreed to pay 25% of the bill each.
If D only paid half of the original 25%, then he only paid 12.5%.
If B and C paid the same, either they split the 12.5% in 6.75% each, or A took the 12.5% and tacked it onto his bill, which seems more likely.
7) There is a point P on the circle. A and B started running in two
constant different speeds. A in Clockwise and B in Anti-clockwise. First
time 500 m in Clockwise from P then 400 Anti-clockwise. If B is yet to
complete one round, What is the circumference of the circle?
Ans:700m
Exp:
Let the speeds of A
& B be u and v resp. and let circumference be C.Let their first meeting be
after time t then ut+vt = C and ut = 500∴ vt = C−500 and u/v = 500/(C−500)For their second meeting after time T, uT+vT =2C and vT = 400
uT = 2C−400 and u/v = (2C−400 )/400
Hence
500/(C−500) = (2C−400) /400
.
Simplifying, 100000 = (C−200)(C−500) = C²−700C+100000 → C=700.....
Simplifying, 100000 = (C−200)(C−500) = C²−700C+100000 → C=700.....
8) There are 11 lines in plane.How many intersections (Maximum) can be made?
Ans:55
Exp:
First line will cut all other 10, similarly second will cut 9, and so on
total = 10+9+8+7+6+5+4+3+2+1 = 55
total = 10+9+8+7+6+5+4+3+2+1 = 55
9) There are 3 Sections with 5 Qns each.
If three Qns are selected from each section, the chance of getting different Qns is?
If three Qns are selected from each section, the chance of getting different Qns is?
Ans:1000
Exp:
Methods for selecting 3 questions out of 5 in the first section = 5*4/2*1 = 10
similarly for others
so total methods = 10*10*10 = 1000
similarly for others
so total methods = 10*10*10 = 1000
10) P # Q = (P-Q)(Q-P) = - 1. Then Which is true?
P = 3, Q = 2 P = 2,Q = 3 P = -1,Q = 1 P = 1, Q = -1
Ans: I & II only
11) 7 Pink, 5 Black, 11 Yellow balls are there. Minimum no. atleast to get one black and yellow ball
Ans: 17
Q2 may be done by another method as:
ReplyDeletex kmph = 5x/18 mps
1000/(10+5x/18) + 1000(10-10x/18) = 187.5
this logic is correct, but still ans is not coming. Can any1 help me in this ?
yeah for me also same problem
Deletei think the speeds will not be in the ratio of 1:2 as the train is also moving. So, the answer with your approach should be the right answer
Delete(1000/x)+(1000/2x)=187.5
Delete(2000+1000)/2x = 187.5
3000/2*187.5 = x
8=x
(1000/(10+x))+(1000/(10-2x))=187.5
Deletebecause of relative speed
even i faced the same problem can anyone expalin
ReplyDeletei think answer for 11 would be 19
ReplyDelete